document.write( "Question 109606This question is from textbook
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document.write( ": 3. Kwan hiked up a hill at 4km/h and back down at 6 km/h. his total hiking time was 3 h. how long did the trip up take him. \n" );
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Algebra.Com's Answer #79898 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let t=time it took Kwan to go up the hill \n" ); document.write( "Then 3-t=time it took him to go down the hill\r \n" ); document.write( "\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "distance up the hill = distance down the hill\r \n" ); document.write( "\n" ); document.write( "distance up=4*t \n" ); document.write( "distance down=6*(3-t)----So:\r \n" ); document.write( "\n" ); document.write( "4t=6(3-t) get rid of parens (distributive law) \n" ); document.write( "4t=18-6t add 6t to both sides\r \n" ); document.write( "\n" ); document.write( "4t+6t=18-6t+6t collect like terms\r \n" ); document.write( "\n" ); document.write( "10t=18 divide both sides by 10 \n" ); document.write( "t=1.8 hr---------------------------------time to go up the hill\r \n" ); document.write( "\n" ); document.write( "3-1.8=1.2 hr-----------------------------time to go down the hill \n" ); document.write( "CK \n" ); document.write( "1.8+1.2=3 \n" ); document.write( "3=3\r \n" ); document.write( "\n" ); document.write( "and \n" ); document.write( "(1.8)*4=(1.2)*6\r \n" ); document.write( "\n" ); document.write( "7.2=7.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---------------------ptaylor \n" ); document.write( " \n" ); document.write( " |