document.write( "Question 1173675: A cabin cruiser leaves a harbour and travels south at 15km/h. One hour later a speed boat leaves the same harbour and travels on the same course at 25 km/h. How far from the harbour will the speed boat pass the cruiser? \n" ); document.write( "

Algebra.Com's Answer #798970 by MathTherapy(10557) $\"\"$ $\"About$

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\n" ); document.write( "A cabin cruiser leaves a harbour and travels south at 15km/h. One hour later a speed boat leaves the same harbour and travels on the same course at 25 km/h. How far from the harbour will the speed boat pass the cruiser?
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Let distance from the harbour, be D
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document.write( "Then time the slower boat took to get to that point = 
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document.write( "And, time the faster took to get to that point = 
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document.write( "We then get the following TIME equation: 
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document.write( "5D = 3D + 75 ------ Multiplying by LCD, 75
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document.write( "5D - 3D = 75
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document.write( "2D = 75
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document.write( "Distance from the harbour, or  \n" );
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