document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173629>Question 1173629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Marlin coin bank has 31 coins consisting of nickles and quarters, worth $6.75. How many quarters are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #798918 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=798918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, you can get some good mental exercise by solving a problem like this using logical reasoning and some simple arithmetic.<br><BR>\n" );
document.write( "(1) If all 31 coins were nickels, their value would be $1.55, which is $5.20 less than the actual value.<BR>\n" );
document.write( "(2) Exchanging a nickel for a quarter keeps the total number of coins the same but increases the value by 20 cents.<BR>\n" );
document.write( "(3) The number of times you need to exchange a nickel for a quarter, to make up the addition $5.20 (i.e., 520 cents), is 520/20 = 26.<br><BR>\n" );
document.write( "So the number of quarters is 26, which leaves 5 coins to be nickels.<br><BR>\n" );
document.write( "CHECK: 26(25)+5(5) = 650+25 = 675<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );