document.write( "Question 1173645: How many different 4-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6, 8, and 9 if no repetition of digits is allowed. \n" ); document.write( "
Algebra.Com's Answer #798916 by greenestamps(13198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The only restriction on the number to be formed, other than the requirement that the digits be all different, is that the number must be even. \n" ); document.write( "That means the units digit must be even; the other digits can be any digits. \n" ); document.write( "Since the only restriction is on the units digit, choose it first. Among the given digits, 4 of them are even, so there are 4 choices for the units digit. \n" ); document.write( "After that, there are 8 digits left to choose from; and you can choose the tens, hundreds, and thousands digits in any order you want. \n" ); document.write( "Because of the requirement that the digits all be different, there are 8 choices for the next digit you choose, 7 choices for the one after that, and 6 choices for the last. \n" ); document.write( "So the total number of 4-digit even numbers that can be formed from the given digits is 4*8*7*6 = 1344 \n" ); document.write( " \n" ); document.write( " |