document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173390>Question 1173390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A basic cellular package costs $30/month for 60 minutes of calling with an additional charge of $0.50/minute beyond that time. The cost function C(x) for using x minutes would be\r<BR>\n" );
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document.write( "If you used 60 minutes or less, i.e. if if x≤60,  then C(x)=30 (the base charge). <BR>\n" );
document.write( "If you used more than 60 minutes, i.e. (x−60) minutes more than the plan came with, you would pay an additional $0.50 for each of those (x−60) minutes. Your total bill would be C(x)=30+0.50(x−60).<BR>\n" );
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document.write( "If you want to keep your bill at $50 or lower for the month, what is the maximum number of calling minutes you can use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #798894 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=798894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C(x)=30+0.50(x-60)<=50<BR>\n" );
document.write( "0.50(x-60)<=20<BR>\n" );
document.write( "0.5x-30<=20<BR>\n" );
document.write( "0.5x < =50<BR>\n" );
document.write( "x <= 100 minutes<BR>\n" );
document.write( "100 minutes is the answer. </SPAN>\n" );
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