document.write( "Question 1173381: Question :
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document.write( "The mean for the number of weeks 15 New York Times hard-cover fiction books spent on the bestseller list is 22 weeks. The standard deviation is 6.17 weeks. The mean for the number of weeks 15 New York Times hard-cover nonfiction books spent on the list is 28 weeks. The standard deviation is 13.2 weeks. At α=0.10, can we conclude that there is a difference in the mean times for the number of weeks the books were on the bestseller lists?\r
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Algebra.Com's Answer #798893 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Ho:means are equal for F and NF \n" ); document.write( "Ha: means are not equal \n" ); document.write( "alpha=0.10 p{reject Ho|Ho true} \n" ); document.write( "test is a 2 sample t \n" ); document.write( "critical value is t(0.95, df=28) is 1.701, reject if |t|>1.701 \n" ); document.write( "calculation is t=(difference between means)/sqrt[ (s1^2/n1)+(s2^2/n2)] \n" ); document.write( "=-6/sqrt [(6.17^2/15)+(13.2^2/15)]; denominator=sqrt(14.15) \n" ); document.write( "=-6/3.76 \n" ); document.write( "=-1.60 \n" ); document.write( "fail to reject Ho; insufficient evidence to say that there is a difference between the means. \n" ); document.write( "p-value=0.13 \n" ); document.write( " |