document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173430>Question 1173430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A SMART company has 500 customers paying Php 600.00 each month. A decrease of Php 30.00 in a monthly payment, they found out that it can attracts 120 additional customers<BR>\n" );
document.write( "1)How much is the total monthly payments if the costumers pay Php 600.00 per month?<BR>\n" );
document.write( "2)How much is the total monthly payments if the costumers pay Php 570.00<BR>\n" );
document.write( "3)Write a quadratic function in standard for that models the revenue R from the payments each per month<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #798821 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=798821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 500 * 600 = 30,0000<BR>\n" );
document.write( "500 is the number of customers<BR>\n" );
document.write( "600 is the amount they pay each month.\r<BR>\n" );
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document.write( "if they drop the amount they pay each month by 30, they will attract 120 more customers.\r<BR>\n" );
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document.write( "the equation to model that would be:\r<BR>\n" );
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document.write( "y = (500 + 120x) * (600 - 30x)\r<BR>\n" );
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document.write( "what this says is that, for every drop in the price of 30, the number of customers will increase by 120.\r<BR>\n" );
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document.write( "y represents the revenue which is a function of demand * price.\r<BR>\n" );
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document.write( "the value of x is the number of times that 30 is dropped from the price and 120 is added to the number of customers.\r<BR>\n" );
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document.write( "when x = 0, the equation becomes y = 500 * 600 which gets you y = 300,000.\r<BR>\n" );
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document.write( "when x = 1, the equation becomes y = 620 * 570 which gets you y = 353,400.\r<BR>\n" );
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document.write( "the equation in standard form is:\r<BR>\n" );
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document.write( "y = -3,600 * x^2 + 57,000 * x + 300,000\r<BR>\n" );
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document.write( "when x = 0, y is equal to 300,000.\r<BR>\n" );
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document.write( "when x = 1, y = -3,600 + 57,000 + 300,000 = 353,400.\r<BR>\n" );
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document.write( "both equations draw the same curve on the graph and provide the same answers for the same value of x.\r<BR>\n" );
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document.write( "this means they are equivalent.\r<BR>\n" );
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document.write( "the graph of both equations is shown below.\r<BR>\n" );
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document.write( "your questions and the answers to them are shown below.\r<BR>\n" );
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document.write( "1)How much is the total monthly payments if the costumers pay Php 600.00 per month?\r<BR>\n" );
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document.write( "the total payments are 500 * 600 = 300,000.\r<BR>\n" );
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document.write( "total payments means the same as total revenue.\r<BR>\n" );
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document.write( "2)How much is the total monthly payments if the costumers pay Php 570.00\r<BR>\n" );
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document.write( "when the price is dropped by 30, the number of customers increases by 120.\r<BR>\n" );
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document.write( "the total payments are 620 * 570 = 353,400.\r<BR>\n" );
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document.write( "3)Write a quadratic function in standard for that models the revenue R from the payments each per month\r<BR>\n" );
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document.write( "the quadratic function in standard form is y = -3,600 * x^2 + 57,000 * x + 300,000.\r<BR>\n" );
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