document.write( "Question 1173386: Question 1:
\n" ); document.write( "A sample of 10 networking sites for a specific month has a mean of 26.1 and a standard deviation of 4.2. Find the 99% confidence interval of the true mean.\r
\n" ); document.write( "\n" ); document.write( "Question 2:
\n" ); document.write( "In a survey of 500 infants chosen at random, it is found that 240 are girls. Are boy and girl births equally likely according to this survey (use α = 0.05)\r
\n" ); document.write( "\n" ); document.write( "Question 9:
\n" ); document.write( "Is the choice of exercise equipment dependent upon gender? Recent records from a large gym indicated the following equipment usage. At the 0.05 level of significance, is there a relationship?\r
\n" ); document.write( "\n" ); document.write( " Treadmill Elliptical Bike
\n" ); document.write( "Male 120 60 75
\n" ); document.write( "Female 100 95 82
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Algebra.Com's Answer #798813 by Boreal(15235)\"\" \"About 
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half-interval is t (0.995, df=9)*s/sqrt(n)
\n" ); document.write( "=3.25*4.2/sqrt(10)
\n" ); document.write( "=4.32
\n" ); document.write( "the 99% C( is (21.8, 30.4)
\n" ); document.write( "-
\n" ); document.write( "Ho: girls=0.5
\n" ); document.write( "Ha: girls NE 0.5
\n" ); document.write( "alpha = 0.0=p(reject Ho|Ho true}
\n" ); document.write( "test stat z=(phat-p)/sqrt (p(1-p)/n)
\n" ); document.write( "critical value |z|>1.96
\n" ); document.write( "z=0.02/sqrt(0.25/500)
\n" ); document.write( "=0.89
\n" ); document.write( "fail to reject Ho. Insufficient evidence to reject the null hypothesis.
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\n" ); document.write( "The expected value are
\n" ); document.write( "105.45--74.3--75.25
\n" ); document.write( "114.55--80.7--81.75
\n" ); document.write( "Chi-Square is 9.14 which has a p-value of 0.01, and the evidence suggests a relationship, not independence.
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