document.write( "Question 1173517: Norman and Susy own 41 shares of restaurant stock and 69 shares of a toy company stock. At the close of the markets on a particular day in 2004, their stock portfolio consisting of these two stocks was worth $1755.00. The closing price of the restaurant stock was $20 more per share than the toy company stock on that day. What was the closing price of each stock on that day? \n" ); document.write( "

Algebra.Com's Answer #798737 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let t be the price per share of the toy company. \r\n" );
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document.write( "Then the price per share of the restaurant stock is (t+20).\r\n" );
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document.write( "An equation for the total stocks is\r\n" );
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document.write( "    69t + 41*(t+20) = 1755\r\n" );
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document.write( "From this equation\r\n" );
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document.write( "        110t        = 1755 - 41*20\r\n" );
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document.write( "        110t        =     935\r\n" );
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document.write( "           t        =      935/110 = 8.5\r\n" );
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document.write( "ANSWER.  The toy company stock was $8.50 per share; the restaurant stock was $28.50 per share. \r\n" );
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