document.write( "Question 109585: I am supposed to find k in the following quadratic equation:\r
\n" ); document.write( "\n" ); document.write( "(k+3)x^2 + 2kx + 4 = 0.\r
\n" ); document.write( "\n" ); document.write( "I have tried using the quadratic formula and unless I'm doing something wrong I don't come up with k. I have tried using the discriminant to find k with no success. I must be missing something easy.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help, Don
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Algebra.Com's Answer #79868 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Are you trying to find a k that yields one real solution? If you are, then the discriminant must equal zero. So \r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2-4ac=0\" which means \"%282k%29%5E2-4%28k%2B3%29%284%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282k%29%5E2-4%28k%2B3%29%284%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"4k%5E2-16k-48=0\"\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for k:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ak%5E2%2Bbk%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"k+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"4%2Ak%5E2-16%2Ak-48=0\" ( notice \"a=4\", \"b=-16\", and \"c=-48\")
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\n" ); document.write( " \"k+=+%28--16+%2B-+sqrt%28+%28-16%29%5E2-4%2A4%2A-48+%29%29%2F%282%2A4%29\" Plug in a=4, b=-16, and c=-48
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\n" ); document.write( " \"k+=+%2816+%2B-+sqrt%28+%28-16%29%5E2-4%2A4%2A-48+%29%29%2F%282%2A4%29\" Negate -16 to get 16
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\n" ); document.write( " \"k+=+%2816+%2B-+sqrt%28+256-4%2A4%2A-48+%29%29%2F%282%2A4%29\" Square -16 to get 256 (note: remember when you square -16, you must square the negative as well. This is because \"%28-16%29%5E2=-16%2A-16=256\".)
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\n" ); document.write( " \"k+=+%2816+%2B-+sqrt%28+256%2B768+%29%29%2F%282%2A4%29\" Multiply \"-4%2A-48%2A4\" to get \"768\"
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\n" ); document.write( " \"k+=+%2816+%2B-+sqrt%28+1024+%29%29%2F%282%2A4%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"k+=+%2816+%2B-+32%29%2F%282%2A4%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"k+=+%2816+%2B-+32%29%2F8\" Multiply 2 and 4 to get 8
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"k+=+%2816+%2B+32%29%2F8\" or \"k+=+%2816+-+32%29%2F8\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%2816+%2B+32%29%2F8\"
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\n" ); document.write( " \"k=48%2F8\" Add the terms in the numerator
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\n" ); document.write( " \"k=6\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"k=6\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%2816+-+32%29%2F8\"
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\n" ); document.write( " \"k=-16%2F8\" Subtract the terms in the numerator
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\n" ); document.write( " \"k=-2\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"k=-2\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"k=6\" or \"k=-2\"
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\n" ); document.write( "\n" ); document.write( "So if k=-2 or k=6, then it will give us one solution for \"%28k%2B3%29x%5E2+%2B+2kx+%2B+4+\"
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