Algebra.Com's Answer #79868 by jim_thompson5910(35256)  You can put this solution on YOUR website! Are you trying to find a k that yields one real solution? If you are, then the discriminant must equal zero. So \r \n" );
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document.write( " which means \r \n" );
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document.write( " \r \n" );
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document.write( " Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for k:
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document.write( " Starting with the general quadratic \n" );
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document.write( " the general solution using the quadratic equation is: \n" );
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document.write( " So lets solve ( notice , , and ) \n" );
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document.write( " Plug in a=4, b=-16, and c=-48 \n" );
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document.write( " Negate -16 to get 16 \n" );
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document.write( " Square -16 to get 256 (note: remember when you square -16, you must square the negative as well. This is because .) \n" );
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document.write( " Multiply to get  \n" );
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document.write( " Combine like terms in the radicand (everything under the square root) \n" );
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document.write( " Simplify the square root (note: If you need help with simplifying the square root, check out this solver) \n" );
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document.write( " Multiply 2 and 4 to get 8 \n" );
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document.write( " So now the expression breaks down into two parts \n" );
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document.write( " or  \n" );
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document.write( " Lets look at the first part: \n" );
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document.write( " Add the terms in the numerator \n" );
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document.write( " Divide \n" );
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document.write( " So one answer is \n" );
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document.write( " Now lets look at the second part: \n" );
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document.write( " Subtract the terms in the numerator \n" );
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document.write( " Divide \n" );
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document.write( " So another answer is \n" );
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document.write( " So our solutions are: \n" );
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document.write( " or  \n" );
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document.write( "So if k=-2 or k=6, then it will give us one solution for \n" );
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