document.write( "Question 1173443: Elizabeth wishes to purchase $3 boxes of cookies and $5 boxes of cookies. She decides to buy 4 fewer $5 boxes than $3 boxes. How many of each box can she buy for no more than $20?
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Algebra.Com's Answer #798646 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x = the number of 3 dollars boxes. \n" ); document.write( "let y = the number of 5 dollar boxes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation will be 3x + 5y <= 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the number of 5 dollars boxes is 1 less than the number of 3 dollars boxes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation for that is y = x - 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in the equation of 3x - 5y <= 20, replace y with x - 4 to get 3x + 5(x-4) <= 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify this equation to get 3x + 5x - 20 <= 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add 20 to both sides of this inequality and combine like terms to get 8x <= 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x <= 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since y = x - 4, then y <= 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 5, y = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 5y <= 20 becomes 3*5 + 5*1 <= 20 which becomes 20 <= 20 which is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "any value of x < 5 will result in y being equal to 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if she wants at least one 5 dollar box, then x must be equal to 5.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |