document.write( "Question 1173385: It takes Erica 50 min to drive to work in the morning. She drives home using the same route, but it takes 21 min longer, and she averages 16 mi/h less than in the morning. How far does Erica drive to work? \n" ); document.write( "
Algebra.Com's Answer #798603 by ikleyn(52834)\"\" \"About 
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\n" ); document.write( "It takes Erica 50 min to drive to work in the morning. She drives home using the same route,
\n" ); document.write( "but it takes 21 min longer, and she averages 16 mi/h less than in the morning. How far does Erica drive to work?
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document.write( "Let \"d\" be the one way distance, in miles (the value under the problem's question).\r\n" );
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document.write( "Driving to work is 50 minutes;  the average rate is  \"d%2F50\"  miles per minute.\r\n" );
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document.write( "Driving back    is 71 minutes;  the average rate is  \"d%2F71\"  miles per minute.\r\n" );
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document.write( "The difference of the average rates is  \"d%2F50\" - \"d%2F71\"  miles per minute.\r\n" );
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document.write( "According to the condition, this difference is  16 miles per hour,  or  \"16%2F60\"  miles per minute.\r\n" );
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document.write( "So, you have this equation\r\n" );
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document.write( "    \"d%2F50\" - \"d%2F71\" = \"16%2F60\".\r\n" );
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document.write( "To solve it, multiply both sides by 50*71*60. You will get\r\n" );
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document.write( "    60*71*d - 60*50*d = 16*50*71\r\n" );
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document.write( "    (60*71 - 60*50)*d = 16*50*71\r\n" );
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document.write( "           d          = \"%2816%2A50%2A71%29%2F%2860%2A71-60%2A50%29\" = 45.079.\r\n" );
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document.write( "ANSWER.  One-way distance is  45.079 miles.\r\n" );
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