document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173293>Question 1173293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1:a production department has 35 similar milling machines.the number of breakdown on each machine average 0.06 per week.determine the probability of having (a):one<BR>\n" );
document.write( "        (B):less than three machines breaking down in any week\r<BR>\n" );
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document.write( "2;A company employing 60 people pays its employees an average wages of TZs 725 an hour with standard deviation of TZS 60.suppose the wages are approximately normally distributed.<BR>\n" );
document.write( "1: determine the number of workers receiving wages between TZS 665 and TZS 770 an hour inclusive<BR>\n" );
document.write( "2: determine the minimum hourly wages received by the highest 5% of the employees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #798586 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=798586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. a. one breakdown is 35*0.06*0.94^34=0.2562<BR>\n" );
document.write( "b. for < 3, look at 0, which has prob. .94^35=0.1147 and 2, which would be 35C2*0.06^2*0.94^33=0.2780<BR>\n" );
document.write( "That sum is 0.6489, when the prob. of 1 is included.<BR>\n" );
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document.write( "2.z=(x-mean)/sd or (665-725)/60 which is -1 and z=(770-725)/60 or 0.75<BR>\n" );
document.write( "That probability is 0.6147. For 60 people, that would be 37 to the nearest integer.<BR>\n" );
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document.write( "the top 5% are at z=1.645\r<BR>\n" );
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document.write( "therefore, 1.645=(x-725)/60<BR>\n" );
document.write( "or 98.7=x-725<BR>\n" );
document.write( "x=TZS 823.69 which can be rounded if needed </SPAN>\n" );
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