document.write( "Question 1173353: A triangular garden has two equal sides 3.6 m long and a contained angle of 80°. Draw and
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\n" ); document.write( "a) How much fencing, to the nearest metre, is needed for this garden?
\n" ); document.write( "b) How much area does the garden cover? Round your answer to the nearest tenth of a square metre
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Algebra.Com's Answer #798575 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "After sketching a line down representing the height of the isosceles Triangle,
\n" ); document.write( "dividing the triangle equally, following applies per sketch of left half
\n" ); document.write( "hypotenuse = 3.6m
\n" ); document.write( "Angle A = 90° - 80°/2 =50°
\n" ); document.write( "cos50° = adj/hyp =b/2.6 ( b= B/2) and sin50° =opp/hyp= height/2.6
\n" ); document.write( "b = 2.6cos50° = 1.7m \"B%5BIsosceles%5D\" = 3.4m and height = 2.6sin50° = 1.99 m
\n" ); document.write( "a) amount of fencing = 2.6m +2.6m + 3.4m
\n" ); document.write( "b) Area = (3.4m)(1.99m)/2
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