document.write( "Question 1173270: Oil Changes A service station advertises that
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document.write( "customers will have to wait no more than 30 minutes for
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document.write( "an oil change. A sample of 28 oil changes has a standard
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document.write( "deviation of 5.2 minutes. Find the 95% confidence
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document.write( "interval of the population standard deviation of the time
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document.write( "spent waiting for an oil change. \n" );
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Algebra.Com's Answer #798503 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! This is a Chi Square with df=27 \n" ); document.write( "(n-1) s^2/ChiSq 0.025, df=27 < sigma ^2 < (n-1)s^2/ChiSq 0.975,df=27 \n" ); document.write( "26*27.04/43.195 < 26*27.04/14.573 Chi Square from the table \n" ); document.write( "=16.28 < sigma ^2 < 48.24 \n" ); document.write( "That is the 95% CI of the variance \n" ); document.write( "take the square root for the CI of the sd \n" ); document.write( "4.03 < sigma < 6.95 \n" ); document.write( "or (4.03, 6.95) units minutes \n" ); document.write( " |