document.write( "Question 1173284: Find four consecutive even integers such that three times the sum of the first and third numbers is equal to four times the sum of the second and fourth numbers. \r
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Algebra.Com's Answer #798490 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi  \r\n" );
document.write( "four consecutive even integers: n , (n+2), (n+4), (n+6)\r\n" );
document.write( "three times the sum of the first and third numbers \r\n" );
document.write( "is equal to four times the sum of the second and fourth numbers. \r\n" );
document.write( "3(n + (n+4)) = 4((n+2) + (n+6))\r\n" );
document.write( "3(2n+4) = 4(2n+8)\r\n" );
document.write( "6n + 12 = 8n + 32\r\n" );
document.write( " -20 = 2n\r\n" );
document.write( "n = -10\r\n" );
document.write( "four consecutive even integers are:  -10, -8, -6, -4 \r\n" );
document.write( "Checking our Answer:\r\n" );
document.write( "3(-16) = 4(-12) = 48  checks!\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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