document.write( "Question 1173284: Find four consecutive even integers such that three times the sum of the first and third numbers is equal to four times the sum of the second and fourth numbers. \r
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Algebra.Com's Answer #798488 by ikleyn(52847) $\"\"$ $\"About$

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document.write( "The numbers are n, (n+2), (n+4) and (n+6), in ascending order.\r\n" );
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document.write( "The equation is\r\n" );
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document.write( "    3*(n + (n+4)) = 4*((n+2) + (n+6))\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "    3*(2n+4) = 4*(2n+8)\r\n" );
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document.write( "    6n + 12  = 8n + 32\r\n" );
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document.write( "    12 - 32  = 8n - 6n\r\n" );
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document.write( "      -20  =   2n\r\n" );
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document.write( "        n  =   = -10.\r\n" );
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document.write( "ANSWER.  The numbers are -10, -8, -6, -4.\r\n" );
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