document.write( "Question 109526: A 100 pound watermelon is 95 percent water. It is dehydrated until it is 90 percent water. What is its weight of dehydration? \n" ); document.write( "
Algebra.Com's Answer #79845 by edjones(8007)\"\" \"About 
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\n" ); document.write( "weight of water/weight of melon = % of water. Assuming water and non-water portions of melon weigh the same.
\n" ); document.write( "95/100=.95
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\n" ); document.write( "Let x=weight of water lost.
\n" ); document.write( "(95-x)/(100-x)=.9
\n" ); document.write( "95-x=.9(100-x)
\n" ); document.write( "95-x=90-.9x
\n" ); document.write( ".1x=5
\n" ); document.write( "x=50 lbs!!!
\n" ); document.write( "Surprising answer.
\n" ); document.write( "So, the watermelon weighs 50 lbs.
\n" ); document.write( ".
\n" ); document.write( "Check:
\n" ); document.write( "45/50=.9
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