document.write( "Question 109526: A 100 pound watermelon is 95 percent water. It is dehydrated until it is 90 percent water. What is its weight of dehydration? \n" ); document.write( "
| Algebra.Com's Answer #79845 by edjones(8007)     You can put this solution on YOUR website! . \n" ); document.write( "weight of water/weight of melon = % of water. Assuming water and non-water portions of melon weigh the same. \n" ); document.write( "95/100=.95 \n" ); document.write( ". \n" ); document.write( "Let x=weight of water lost. \n" ); document.write( "(95-x)/(100-x)=.9 \n" ); document.write( "95-x=.9(100-x) \n" ); document.write( "95-x=90-.9x \n" ); document.write( ".1x=5 \n" ); document.write( "x=50 lbs!!! \n" ); document.write( "Surprising answer. \n" ); document.write( "So, the watermelon weighs 50 lbs. \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "45/50=.9 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |