document.write( "Question 1173185: A dog trainer has 88 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 420 ft2, what will be the dimensions of the work area? \n" ); document.write( "
Algebra.Com's Answer #798436 by Alan3354(69443)\"\" \"About 
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A dog trainer has 88 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 420 ft2, what will be the dimensions of the work area?
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\n" ); document.write( "Area = L*W = 420
\n" ); document.write( "P = 2*(L + W) = 88
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\n" ); document.write( "L*W = 420
\n" ); document.write( "L + W = 44 ---> L = 44-W
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\n" ); document.write( "W*(44-W) = 420
\n" ); document.write( "W^2 - 44W = -420
\n" ); document.write( "W^2 - 44W + 484 = -420+484 = 64
\n" ); document.write( "(W-22)^2 = 64
\n" ); document.write( "W-22 = 8
\n" ); document.write( "W = 30
\n" ); document.write( "L = 14\r
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