document.write( "Question 1173185: A dog trainer has 88 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 420 ft2, what will be the dimensions of the work area? \n" ); document.write( "
Algebra.Com's Answer #798436 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A dog trainer has 88 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 420 ft2, what will be the dimensions of the work area? \n" ); document.write( "============================== \n" ); document.write( "Area = L*W = 420 \n" ); document.write( "P = 2*(L + W) = 88 \n" ); document.write( "------------- \n" ); document.write( "L*W = 420 \n" ); document.write( "L + W = 44 ---> L = 44-W \n" ); document.write( "----- \n" ); document.write( "W*(44-W) = 420 \n" ); document.write( "W^2 - 44W = -420 \n" ); document.write( "W^2 - 44W + 484 = -420+484 = 64 \n" ); document.write( "(W-22)^2 = 64 \n" ); document.write( "W-22 = 8 \n" ); document.write( "W = 30 \n" ); document.write( "L = 14\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |