document.write( "Question 1173231: Two boats leave a harbour at the same time and head out at an angle of 35o to each other. Boat A is travelling at 45 km/h and boat B is travelling at 52 km/h. How far apart are the two boats after two hours? \n" ); document.write( "

Algebra.Com's Answer #798424 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi  
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document.write( "Two boats leave a harbour at the same time and head out at an angle of 35o to each other
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document.write( "Boat A is travelling at 45 km/h and boat B is travelling at 52 km/h. 
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document.write( "How far apart are the two boats after two hours?
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document.write( "Viewing the boats traveling forming a  Right Triangle ∠A = 35°     
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document.write( "one boat travels 90m (along b), the other 104m(along c)
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document.write( "Distance apart will be a on the picture
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document.write( "C^2 = a^2 + b^2
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document.write( "(104)^2 = a^2 + (90)^2
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document.write( "10816= a^2 + 8100 
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document.write( "10816 - 8100 = a^2
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document.write( "2716 = a^2 
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document.write( "a = 52.115km
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document.write( "Assuming the travel would result in a Right Triangle may not be the case:
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document.write( "Yes, Best to use cosine Law to cover all the bases.
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document.write( " = 62.234km
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document.write( "In this case, travel didn't end up representing the model of a right Triangle.
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document.write( "Wish You the Best in your Studies. \n" );
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