document.write( "Question 1173159: Suppose that on a highway, an average of four accidents occur per day.
\n" ); document.write( "a) State the parameter for this probability distribution.
\n" ); document.write( "b) Calculate the mean and standard deviation for this probability distribution.
\n" ); document.write( "c) What is the probability that an accident will occur on a particular day?
\n" ); document.write( "d) Find the probability that from 4 to 6 accidents will occur from 1:00pm to 7:00pm on a particular day.
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Algebra.Com's Answer #798416 by Boreal(15235)\"\" \"About 
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This is a Poisson distribution- counts, proportional to time, could theoretically be infinite.
\n" ); document.write( "Parameter is 4.
\n" ); document.write( "Mean is 4 accidents a day, variance is 4 acc^2/day^2 and SD is 2 accidents/day
\n" ); document.write( "that is 1-probability no accidents occurs on a day. The latter is e^(-4) or 0.0183, so the answer is 1-0.0183 or 0.9817.
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\n" ); document.write( "A 6 hour period would be expected to have 1 accident during that time, since it is 1/4 of a day so 1/4 of 4 accidents is 1.
\n" ); document.write( "Instead of e^(-4)*4^k/k! we have scaled it down to 1/4 of that so the distribution is e^(-1)*1^k/k!
\n" ); document.write( "p(4)=e^(-1)1^4/4!=0.0153
\n" ); document.write( "p(5)=e^(-1)*1^5/120=0.0031
\n" ); document.write( "p(6)=0.0005 (the denominator is 6! or 720.
\n" ); document.write( "The overall probability is 0.0189.
\n" ); document.write( "This would be low probability, because one would be expecting the usual number of daily accidents to occur in 1/4 of the time.
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