document.write( "Question 1173191: What is the maximum and minimum amount of a drug remaining in a patient
\n" ); document.write( "in the limit (that is, as time tends to infinity) given that the patient takes an 80 milligram dose once a day at the same time each day and the drug has a half life of 22 hours?
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Algebra.Com's Answer #798402 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi  \r\n" );
document.write( "Using Half life Formula:\r\n" );
document.write( ".5 = 80e^(-(22/24)k)\r\n" );
document.write( "ln(.5)/(-22/24) = k\r\n" );
document.write( "k = -.7562\r\n" );
document.write( "Q(t) = 80e^(-.7562)t   (t in days)\r\n" );
document.write( "Takes basically 2 weeks for a daily dose taken previously to leave the body\r\n" );
document.write( "Q(14days) = .002mg  for example\r\n" );
document.write( "total on board on the 14 day of dosing is 150.7844mg\r\n" );
document.write( "Maximum: 150.8mg (desired maintenance level) same as previously determined\r\n" );
document.write( "As to minimum, once one began with a single dose: Appears prior to 2nd dosage = 42.4mg\r\n" );
document.write( "Found Interesting - already at 150.4mg on the 7th day of dosing...\r\n" );
document.write( "Once 7th dosage has been taken:\r\n" );
document.write( "80      7th dosage\r\n" );
document.write( "37.5558 6th remaining\r\n" );
document.write( "17.6304 5th remaining\r\n" );
document.write( "8.2766  4th remaining\r\n" );
document.write( "3.8854  3rd remaining\r\n" );
document.write( "1.824   2nd remaining\r\n" );
document.write( " .402   1st remaining\r\n" );
document.write( "0.8563\r\n" );
document.write( "150.4mg\r\n" );
document.write( "Responded as was interested in mathematically watching it reach the maintenance level, \r\n" );
document.write( "as am on a maintenance prescription for A Fib.\r\n" );
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