document.write( "Question 1173192: In the regular hexagram shown at the bottom, Line AB=4 cm. The area of the hexagram, in cm^2 is:\r
\n" ); document.write( "\n" ); document.write( "A) 48 √ 3
\n" ); document.write( "B) 24 √ 3
\n" ); document.write( "C) 18 √ 3
\n" ); document.write( "D) 20 √ 3
\n" ); document.write( "E)22 √ 3\r
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Algebra.Com's Answer #798371 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "The area of an equilateral triangle with side length x is \"A+=+%28sqrt%283%29%2F4%29%2Ax%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "For equilateral triangle ABC, we have x = 4 as the side length. The area of triangle ABC is
\n" ); document.write( "\"A+=+%28sqrt%283%29%2F4%29%2Ax%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+%28sqrt%283%29%2F4%29%2A4%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+sqrt%283%29%2A%281%2F4%29%2A16\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+sqrt%283%29%2A4\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+4%2Asqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "The regular hexagram is composed of a regular hexagon with equilateral triangles attached to each of the six edges of the hexagon.
\n" ); document.write( "We can break up the regular hexagon into 6 equilateral triangles that are all congruent to one another. These 6 additional triangles are identical to the triangles that line the outside of the hexagon.\r
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\n" ); document.write( "\n" ); document.write( "In short: we have 6+6 = 12 equilateral triangles that are identical.\r
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\n" ); document.write( "\n" ); document.write( "Because we have 12 identical triangles, each with area \"A+=+4%2Asqrt%283%29\", this means the total area of the regular hexagram is \"12A+=+12%2A4%2Asqrt%283%29+=+48%2Asqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer: A) 48 √ 3
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