document.write( "Question 1172999: At what rate, compounded monthly should P25, 000 be deposited in a bank to gain an interest of P4,500 in 3 years? \n" ); document.write( "
Algebra.Com's Answer #798308 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "At what rate, compounded monthly should P25,000 be deposited in a bank to gain an interest of P4,500 in 3 years?
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\n" ); document.write( "\n" ); document.write( "            It is one of the typical problems on periodically compounded account,
\n" ); document.write( "            but slightly changed/modified comparing with traditional formulation.\r
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\n" ); document.write( "\n" ); document.write( "            So,  my first step is  to convert  the problem to its traditional form.\r
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\n" ); document.write( "\n" ); document.write( "            To convert it,  notice that having the principal of  P25,000  and gaining the interest of  P4,500 \r
\n" ); document.write( "\n" ); document.write( "            MEANS  that the  Future  Value  is   P25,000 + P4,500 = P29,500.\r
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\n" ); document.write( "\n" ); document.write( "            So,  now we have this traditional formulation\r
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document.write( "           |   Find the nominal annual rate at which the principal P25,000  |\r\n" );
document.write( "           |   compounded monthly becomes P29,500 in 3 years ?              |\r\n" );
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\n" ); document.write( "\n" ); document.write( "Now this standard problem is  EASY  to  SOLVE.\r
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document.write( "    29500 = \"25000%2A%281%2Br%2F12%29%5E%283%2A12%29\"\r\n" );
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document.write( "    \"29500%2F25000\" = \"%281%2Br%2F12%29%5E36\"\r\n" );
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document.write( "    \"%281%2Br%2F12%29%5E36\" = 1.18\r\n" );
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document.write( "    \"log%2810%2C%281+%2B+r%2F12%29%29\" = \"%281%2F36%29%2Alog%2810%2C%281.18%29%29\" = 0.001997\r\n" );
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document.write( "    \"1+%2B+r%2F12\"  = \"10%5E0.001997\" = 1.004609.\r\n" );
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document.write( "      \"r%2F12\"    = 1.004609 - 1 = 0.004609\r\n" );
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document.write( "        r    = 12*0.004609 = 0.055308 = 0.055 (rounded) = 5.5%.    ANSWER\r\n" );
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document.write( "CHECK.  \"25000%2A%281%2B0.055308%2F12%29%5E%283%2A12%29\" = 29500.84.   Good enough.\r\n" );
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