document.write( "Question 1173129: Suppose that the weight of an newborn fawn is Uniformly distributed between 1.7 and 3.5 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible.\r
\n" ); document.write( "\n" ); document.write( "a. The mean of this distribution is
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\n" ); document.write( "c. The probability that fawn will weigh exactly 2.1 kg is P(x = 2.1) =
\n" ); document.write( "d. The probability that a newborn fawn will be weigh between 2.4 and 2.8 is P(2.4 < x < 2.8) =
\n" ); document.write( "e. The probability that a newborn fawn will be weigh more than 2.76 is P(x > 2.76) =
\n" ); document.write( "f. P(x > 2 | x < 3.1) =
\n" ); document.write( "g. Find the 78th percentile.\r
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Algebra.Com's Answer #798306 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi  
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document.write( "Previously Posted
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document.write( "Suppose that the weight of an newborn fawn is Uniformly distributed between 1.7 and 3.5 kg. 
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document.write( "Uniform Distribution a = 1.7 and b= 3.5
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document.write( ",  and  
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document.write( "Uniform and Continuous
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document.write( "P(x = 2.1) = 0  Continuous Distribution
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document.write( "P(2.4 < x < 2.8) = .4(5/9) = 2/9
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document.write( "---
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document.write( "P(x > 2.76) = (3.5 - 2.76)(5/9) = .74(5/9)
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document.write( "---
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document.write( "P(x > 2 | x < 3.1) = (3.5-2)(1/.4)      |f(x) = 1/(b-a) = 1/(3.5-3.1) = 1/.4 
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document.write( "78%
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document.write( "P(x < k) = 
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document.write( " k =   1.7 + (.4)(.78)
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document.write( "Wish You the Best in your Studies. 
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