document.write( "Question 16384: 5x+5y=40
\n" ); document.write( "-5x+4y=-4
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Algebra.Com's Answer #7983 by elima(1433)\"\" \"About 
You can put this solution on YOUR website!
We will solve this one using elimination so we can find what one variable =;
\n" ); document.write( "We begin by adding the two equations toogether;
\n" ); document.write( "5x+5y=40
\n" ); document.write( "-5x+4y=-4
\n" ); document.write( "----------
\n" ); document.write( "9y=36
\n" ); document.write( "Divide both sides by 9
\n" ); document.write( "\"9y%2F9=36%2F9\"
\n" ); document.write( "y=4
\n" ); document.write( "Now we have what y=, so now we can solve for x;
\n" ); document.write( "5x+5(4)=40
\n" ); document.write( "5x+20=40
\n" ); document.write( "5x=40-20
\n" ); document.write( "5x=20
\n" ); document.write( "x=4
\n" ); document.write( "So now we have;
\n" ); document.write( "x=4
\n" ); document.write( "y=4
\n" ); document.write( "Hope you understand
\n" ); document.write( "=)
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