document.write( "Question 109500This question is from textbook Intermediate algebra
\n" ); document.write( ": X2/3 + 4X1/3 - 12 = 0 \n" ); document.write( "
Algebra.Com's Answer #79829 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
X2/3 + 4X1/3 - 12 = 0
\n" ); document.write( "-----
\n" ); document.write( "Let w = x^(1/3)
\n" ); document.write( "Rewrite the equation:
\n" ); document.write( "w^2 + 4w -12 = 0
\n" ); document.write( "(w+4)(w-3)=0
\n" ); document.write( "w = -4 or w=3
\n" ); document.write( "-----------
\n" ); document.write( "x^(1/3) = -4
\n" ); document.write( "x = -64
\n" ); document.write( "--------------
\n" ); document.write( "x^(1/3)=3
\n" ); document.write( "x = 27
\n" ); document.write( "===========
\n" ); document.write( "Solutions:
\n" ); document.write( "x= -64 or x= 27
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );