document.write( "Question 109500This question is from textbook Intermediate algebra
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document.write( ": X2/3 + 4X1/3 - 12 = 0 \n" );
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Algebra.Com's Answer #79829 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! X2/3 + 4X1/3 - 12 = 0 \n" ); document.write( "----- \n" ); document.write( "Let w = x^(1/3) \n" ); document.write( "Rewrite the equation: \n" ); document.write( "w^2 + 4w -12 = 0 \n" ); document.write( "(w+4)(w-3)=0 \n" ); document.write( "w = -4 or w=3 \n" ); document.write( "----------- \n" ); document.write( "x^(1/3) = -4 \n" ); document.write( "x = -64 \n" ); document.write( "-------------- \n" ); document.write( "x^(1/3)=3 \n" ); document.write( "x = 27 \n" ); document.write( "=========== \n" ); document.write( "Solutions: \n" ); document.write( "x= -64 or x= 27 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |