document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173127>Question 1173127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. 1. Solve the quadratic equation <BR>\n" );
document.write( "x^2 − 2x − 3 = 0.\r<BR>\n" );
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document.write( "2. Factor 3x^3 − 12x<BR>\n" );
document.write( "3. Rationalize 5/3\sqrt{x} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #798287 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=798287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor into (x-3)(x+1)=0<BR>\n" );
document.write( "x=3, -1<BR>\n" );
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document.write( "factor out the common factors 3 and x<BR>\n" );
document.write( "3x(x^2-4). Now there is a difference of squares, which may be factored<BR>\n" );
document.write( "3x(x+2(x-2)<BR>\n" );
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document.write( "The last isn't clear.<BR>\n" );
document.write( "(5/3)/sqrt(x)?  If that is it multiply top and bottom by sqrt (x) for (5/3) sqrt(x)/x<BR>\n" );
document.write( "If it is 5/(3 sqrt(x)), multiply top and bottom by sqrt(x) to get 5sqrt(x)/3x\r<BR>\n" );
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document.write( " </SPAN>\n" );
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