document.write( "Question 1173094: A bus comes by every 7 minutes. The times from when a person arives at the bus stop until the bus arrives follows a Uniform distribution from 0 to 7 minutes. A person arrives at the bus stop at a randomly selected time. Round to 4 decimal places where possible.\r
\n" ); document.write( "\n" ); document.write( "a. The mean of this distribution is
\n" ); document.write( "b. The standard deviation is
\n" ); document.write( "c. The probability that the person will wait more than 3 minutes is
\n" ); document.write( "d. Suppose that the person has already been waiting for 1 minutes. Find the probability that the person's total waiting time will be between 2.1 and 3 minutes
\n" ); document.write( "e. 56% of all customers wait at least how long for the train?
\n" ); document.write( " minutes.
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Algebra.Com's Answer #798277 by Boreal(15235)\"\" \"About 
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The mean is the midpoint between the ends or 3.5 min
\n" ); document.write( "variance is (b-a)^2/12 or 49/12 or 4.0833 min
\n" ); document.write( "sd is sqrt(V)=2.02 min
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\n" ); document.write( "wait more than 3 min is (4/7), which may be converted to the decimal.
\n" ); document.write( "waiting 1 minute. The total waiting time must be between 2.1 and 3 minutes. That means the person will wait between 2.1 and 3 minutes 0.9 minute range, with 6 minutes to go, since the clock has started.
\n" ); document.write( "That is 0.1500 probability.
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\n" ); document.write( "56% wait 3.92 minutes, 7*0.56
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