document.write( "Question 1173031: Five years ago Barbra was four-fifths Bill's age then. In ten years she will be
\n" ); document.write( "seven-eights his age then.
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Algebra.Com's Answer #798224 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The responses from the other tutors use what is probably the algebraic method typically seen in textbooks to find the answer. Here is an alternative that I find makes finding the answer easier.

\n" ); document.write( "Given that 5 years ago Barbra was 4/5 of Bill's age, let their ages 5 years ago be 4x and 5x.

\n" ); document.write( "\"10 years from now\" is 15 years after \"5 years ago\"; so their ages 10 years from now will be 4x+15 and 5x+15.

\n" ); document.write( "The ratio of their ages then will be 7/8:

\n" ); document.write( "\"%284x%2B15%29%2F%285x%2B15%29+=+7%2F8\"
\n" ); document.write( "\"8%284x%2B15%29+=+7%285x%2B15%29\"
\n" ); document.write( "\"32x%2B120+=+35x%2B105\"
\n" ); document.write( "\"3x=15\"
\n" ); document.write( "\"x=5\"

\n" ); document.write( "Their ages 5 years ago were:
\n" ); document.write( "Barbra: 4x = 20
\n" ); document.write( "Bill: 5x = 25

\n" ); document.write( "So their current ages are 25 and 30.

\n" ); document.write( "Their ages 10 years from now will be 35 and 40 -- a ratio of 7:8.

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