document.write( "Question 1173031: Five years ago Barbra was four-fifths Bill's age then. In ten years she will be
\n" );
document.write( "seven-eights his age then.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #798224 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The responses from the other tutors use what is probably the algebraic method typically seen in textbooks to find the answer. Here is an alternative that I find makes finding the answer easier. \n" ); document.write( "Given that 5 years ago Barbra was 4/5 of Bill's age, let their ages 5 years ago be 4x and 5x. \n" ); document.write( "\"10 years from now\" is 15 years after \"5 years ago\"; so their ages 10 years from now will be 4x+15 and 5x+15. \n" ); document.write( "The ratio of their ages then will be 7/8: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Their ages 5 years ago were: \n" ); document.write( "Barbra: 4x = 20 \n" ); document.write( "Bill: 5x = 25 \n" ); document.write( "So their current ages are 25 and 30. \n" ); document.write( "Their ages 10 years from now will be 35 and 40 -- a ratio of 7:8. \n" ); document.write( " \n" ); document.write( " |