document.write( "Question 1173032: 8% of all Americans live in poverty. If 30 Americans are randomly selected, find the probability that\r
\n" ); document.write( "\n" ); document.write( "a. Exactly 2 of them live in poverty. \r
\n" ); document.write( "\n" ); document.write( "b. At most 2 of them live in poverty. \r
\n" ); document.write( "\n" ); document.write( "c. At least 1 of them live in poverty. \r
\n" ); document.write( "\n" ); document.write( "d. Between 1 and 5 (including 1 and 5) of them live in poverty. \r
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Algebra.Com's Answer #798197 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "p = .08 n = 30
\n" ); document.write( "P (x = 2) = binompdf(30,.08,2) = .2696
\n" ); document.write( "P( x < 2) = binomcdf(30,.08,1) = .2958
\n" ); document.write( "P ( x ≤ 1 = binomcdf(30,.08,1)= .2958
\n" ); document.write( "P (1 ≤ x ≤ 5) = P(x ≤ 5) - P(x< 1) = .9707 - .082 = .8887
\n" ); document.write( "Recommend until You are comfortable using YOUR statistical Calculator,
\n" ); document.write( "to check YOUR findings with the stattrek calculator on line.
\n" ); document.write( "Wish You the Best in your Studies. \n" ); document.write( "
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