document.write( "Question 1173019: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #798175 by josgarithmetic(39618)\"\" \"About 
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w, woman
\n" ); document.write( "d, daughter
\n" ); document.write( "\"system%28w-6=3%28d-6%29%2Cw-6%2Bd-6=36%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"w-6=3d-18\"
\n" ); document.write( "\"w-3d=-12\"
\n" ); document.write( "\"-w%2B3d=12\"\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"w%2Bd=36%2B12\"
\n" ); document.write( "\"w%2Bd=48\"\r
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\n" ); document.write( "\n" ); document.write( "Very Simple System:
\n" ); document.write( "\"system%28-w%2B3d=12%2Cw%2Bd=48%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ADD: \"4d=60\"
\n" ); document.write( "\"highlight%28d=15%29\"
\n" ); document.write( "-
\n" ); document.write( "\"highlight%28w=33%29\"
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