document.write( "Question 109469: ABCD is a parllelogram,AE perpendicular to DC and CF perpendicular to AD.If AB=16cm,AE=8cm and CF=10cm,find AD \n" ); document.write( "
Algebra.Com's Answer #79817 by Edwin McCravy(20056)\"\" \"About 
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ABCD is a parllelogram,AE perpendicular to DC and CF
\n" ); document.write( "perpendicular to AD. If AB=16cm,AE=8cm and CF=10cm,find AD
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document.write( "Angle CDF = Angle ADE because they are opposite angles formed \r\n" );
document.write( "by two intersecting lines CE and AF\r\n" );
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document.write( "Angle CFD = Angle AED = 90° because AE perpendicular to \r\n" );
document.write( "DC and CF perpendicular to AD. \r\n" );
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document.write( "Triangle CDF is similar to triangle ADE because they have\r\n" );
document.write( "two angles with the same measure.  \r\n" );
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document.write( "\"%28CD%29%2F%28CF%29\" = \"%28AD%29%2F%28AE%29\" because of corresponding \r\n" );
document.write( "sides of similar triangles are proportional. \r\n" );
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document.write( "CD = AB = 16cm because they are opposite sides of a parallelogram\r\n" );
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document.write( "Since CD = 16cm , CF = 10cm, AE = 8cm, the above proportion \r\n" );
document.write( "becomes:\r\n" );
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document.write( "\"16%2F10\" = \"%28AD%29%2F8\"\r\n" );
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document.write( "Cross-multiplying,\r\n" );
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document.write( "\"10%28AD%29\" = \"16%2A8\"\r\n" );
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document.write( "\"10%28AD%29\" = \"128\"\r\n" );
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document.write( "\"AD\" = \"128%2F10\"\r\n" );
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document.write( "\"AD\" = \"12.8cm\"\r\n" );
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document.write( "Edwin

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