document.write( "Question 1173009: it is claimed that people drive on the average 18.000 km per year. A consumer form believes that the average mileage is probably lower. to check, the consumer firm abtained information from 40 randomly selected car owners that resulted in a sample mean of 17, 463 km with a sample standard deviation of 1348 km what can we conclude about this claim? use alpha \n" ); document.write( "
Algebra.Com's Answer #798169 by Theo(13342)![]() ![]() You can put this solution on YOUR website! claim is 18,000 km per year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sample of 40 randomly selected car owners results in a sample mean of 17,463 km with a sample standard deviation of 1348 km.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard error = standard deviation of sample divided by square root of sample size = 1348 / sqrt(40) = 213.375143\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the standard deviation is taken from the sample, then you use t-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t-score = (x - m) / s \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get: \n" ); document.write( "t-score = (17,463 - 18,000) / 213.375143 = -2.515584261.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area to the left of that under the normal distribution curve is equal to .0080345273.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 99% confidence level, the area to the left is less than .01. \n" ); document.write( "this means the results are significant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that the claim that the average mileage is probably lower is valid at the 99% confidence level.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with t-score, you need to use degrees of freedom. \n" ); document.write( "with a sample size of 40, the degrees of freedom is 39.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i used the ti-84 plus to solve for the area to the left of the indicated z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "an online calculator that does the same can be found at https://stattrek.com/online-calculator/t-distribution.aspx\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it provided the same answer rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |