document.write( "Question 1173019: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #798168 by VFBundy(438)\"\" \"About 
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Daughter's age six years ago = d
\n" ); document.write( "Mother's age six years ago = 3d
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\n" ); document.write( "d + 3d = 36
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\n" ); document.write( "4d = 36
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\n" ); document.write( "d = 9
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\n" ); document.write( "Daughter's age six years ago = d = 9
\n" ); document.write( "Mother's age six years ago = 3d = 3(9) = 27
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\n" ); document.write( "Daughter's age today = 9 + 6 = 15
\n" ); document.write( "Mother's age today = 27 + 6 = 33
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