document.write( "Question 1173019: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #798168 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! Daughter's age six years ago = d \n" ); document.write( "Mother's age six years ago = 3d \n" ); document.write( " \n" ); document.write( "d + 3d = 36 \n" ); document.write( " \n" ); document.write( "4d = 36 \n" ); document.write( " \n" ); document.write( "d = 9 \n" ); document.write( " \n" ); document.write( "Daughter's age six years ago = d = 9 \n" ); document.write( "Mother's age six years ago = 3d = 3(9) = 27 \n" ); document.write( " \n" ); document.write( "Daughter's age today = 9 + 6 = 15 \n" ); document.write( "Mother's age today = 27 + 6 = 33 |