document.write( "Question 1172937: Officer Mark has 300 m of yellow tape to seal off the area of a crime scene. Using the tape, he must divide the area
\n" ); document.write( "into four identical rectangular sections, side by side. What dimensions of the crime scene will maximize the area?
\n" ); document.write( "What is the maximum area that can be enclosed?
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Algebra.Com's Answer #798075 by ankor@dixie-net.com(22740)\"\" \"About 
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Officer Mark has 300 m of yellow tape to seal off the area of a crime scene. Using the tape, he must divide the area into four identical rectangular sections, side by side.
\n" ); document.write( " What dimensions of the crime scene will maximize the area?
\n" ); document.write( "To divide into 4 areas, it requires 5 dividing sides and 2 lengths
\n" ); document.write( "2L + 5w = 300
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + 2.5w = 150
\n" ); document.write( "L = 150 - 2.5w
\n" ); document.write( "Area = L*w
\n" ); document.write( "replace L with (150-2.5w)
\n" ); document.write( "A = w(150-2.5w)
\n" ); document.write( "A = 150w - 2.5w^2
\n" ); document.write( "A quadratic equation where b=150 and a=-2.5
\n" ); document.write( "The max area occurs on the axis of symmetry, find that using x=-b/(2a)
\n" ); document.write( "w = \"%28-150%29%2F%282%2A-2.5%29\"
\n" ); document.write( "w = 30 meters is the width
\n" ); document.write( "Find the length
\n" ); document.write( "L = 150 - 2.5(30)
\n" ); document.write( "L = 75 meters is the length
\n" ); document.write( ":
\n" ); document.write( "What is the maximum area that can be enclosed?
\n" ); document.write( " 75 * 30 = 2250 sq meters
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