document.write( "Question 1172937: Officer Mark has 300 m of yellow tape to seal off the area of a crime scene. Using the tape, he must divide the area
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document.write( "into four identical rectangular sections, side by side. What dimensions of the crime scene will maximize the area?
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document.write( "What is the maximum area that can be enclosed? \n" );
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Algebra.Com's Answer #798075 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Officer Mark has 300 m of yellow tape to seal off the area of a crime scene. Using the tape, he must divide the area into four identical rectangular sections, side by side. \n" ); document.write( " What dimensions of the crime scene will maximize the area? \n" ); document.write( "To divide into 4 areas, it requires 5 dividing sides and 2 lengths \n" ); document.write( "2L + 5w = 300 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "L + 2.5w = 150 \n" ); document.write( "L = 150 - 2.5w \n" ); document.write( "Area = L*w \n" ); document.write( "replace L with (150-2.5w) \n" ); document.write( "A = w(150-2.5w) \n" ); document.write( "A = 150w - 2.5w^2 \n" ); document.write( "A quadratic equation where b=150 and a=-2.5 \n" ); document.write( "The max area occurs on the axis of symmetry, find that using x=-b/(2a) \n" ); document.write( "w = \n" ); document.write( "w = 30 meters is the width \n" ); document.write( "Find the length \n" ); document.write( "L = 150 - 2.5(30) \n" ); document.write( "L = 75 meters is the length \n" ); document.write( ": \n" ); document.write( "What is the maximum area that can be enclosed? \n" ); document.write( " 75 * 30 = 2250 sq meters \n" ); document.write( " |