document.write( "Question 1172906: Rectangles A and B are both four times as long as they are wide and the length of rectangle A is three times the length of rectangle B. If the difference in the perimeters is 16cm, find the dimensions of each rectangle. \n" ); document.write( "
Algebra.Com's Answer #798052 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Rectangles A and B are both four times as long as they are wide \n" ); document.write( " and the length of rectangle A is three times the length of rectangle B. \n" ); document.write( " If the difference in the perimeters is 16cm, find the dimensions of each rectangle. \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "let w = width of rectangle B \n" ); document.write( "then \n" ); document.write( "4w = the length of rectangle B \n" ); document.write( "And \n" ); document.write( "3(4w) = 12w = the length of rectangle A \n" ); document.write( "3w = the width of rectangle A, (1/4th of A's length) \n" ); document.write( ": \n" ); document.write( "2(12w + 3w) - 2(4w + w) = 16 \n" ); document.write( "simplify, divide equation by 2 \n" ); document.write( "(12w + 3w) - (4w+w) = 8 \n" ); document.write( "15w - 5w = 8 \n" ); document.write( "10w = 8 \n" ); document.write( "w = 8/10 \n" ); document.write( "w = .8 cm is the width of rectangle B \n" ); document.write( "and \n" ); document.write( "4(.8) = 3.2 cm is length of rectangle B \n" ); document.write( "then \n" ); document.write( "3(.8) = 2.4 cm is width of rectangle A \n" ); document.write( "and \n" ); document.write( "4(2.4) = 9.6 is length of rectangle B \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "see if this checks out \n" ); document.write( "2(9.6 + 2.4) - 2(3.2 + .8) = \n" ); document.write( "2(12) - 2(4) = \n" ); document.write( "24 - 8 = 16 \n" ); document.write( " |