document.write( "Question 1172801: Grade point averages of students on a large campus
\n" ); document.write( "follow a normal distribution with a mean of 2.6 and a
\n" ); document.write( "standard deviation of 0. 5.
\n" ); document.write( "a. One student is chosen at random from this cam-
\n" ); document.write( "pus. What is the probability that this student has a
\n" ); document.write( "grade point average higher than 3.0?
\n" ); document.write( "b. One student is chosen at random from this cam-
\n" ); document.write( "pus. What is the probability that this student has a
\n" ); document.write( "grade point average between 2.25 and 2.75?
\n" ); document.write( "c. What is the minimum grade point average needed
\n" ); document.write( "for a student's grade point average to be among
\n" ); document.write( "the highest 10% on this campus?
\n" ); document.write( "d. A random sample of 400 students is chosen from
\n" ); document.write( "this campus. What is the probability that at least 80
\n" ); document.write( "of these students have grade point averages higher
\n" ); document.write( "than 3.0?
\n" ); document.write( "e. Two students are chosen at random from this
\n" ); document.write( "campus. What is the probability that at least one of
\n" ); document.write( "them has a grade point average higher than 3.0?
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Algebra.Com's Answer #798024 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
z=(x-mean)/sd
\n" ); document.write( ">(3.0-2.6)/0.5 or >0.8. Note; > or >= are the same since this is area from a given dimensionless point on the curve.
\n" ); document.write( "probability is 0.2119
\n" ); document.write( "-
\n" ); document.write( "this is z between -0.7 and +0.3 is 0.3759. Also 2nd VARS2Normalcdf(2.25,2.75,2.6,0.5)ENTER
\n" ); document.write( "-
\n" ); document.write( "the highest 10% is where z=1.282
\n" ); document.write( "1.282=(x-2.6)/0.5
\n" ); document.write( "0.641=x-2.6
\n" ); document.write( "x=3.241
\n" ); document.write( "-
\n" ); document.write( "The probability of 1 being > 3.0 is 0.21185
\n" ); document.write( "for 80/400 or 0.2, do a 1 proportion z test
\n" ); document.write( "z>(0.2-0.21185)/sqrt(0.21185*0.78815/400)
\n" ); document.write( "z>-0.01185/0.0204=-0.5801
\n" ); document.write( "that probability is 0.7191 (calculator gives 0.7190)
\n" ); document.write( "-
\n" ); document.write( "What is the probability that neither has that value? That is 0.7881^2 or 0.6211. So the answer is the complement of that value or 0.3789
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