document.write( "Question 1172878: The slant height of a cone is doubled. Does this double the surface area of the cone? Explain your
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Algebra.Com's Answer #798022 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The lateral surface area of a cone is \"%28pi%29%28r%29%28l%29\", where r is the radius of the base and l is the slant height.

\n" ); document.write( "The area of the base is \"%28pi%29%28r%5E2%29\".

\n" ); document.write( "The intent of the question is not clear....

\n" ); document.write( "(1) If only the slant height of the cone is doubled (the radius of the cone is unchanged), then the LATERAL surface area is doubled. The (total) surface area of the cone -- which is literally what the question asks for, is NOT doubled, because the surface area of the base does not change.

\n" ); document.write( "(2) If the \"new\" cone is similar to the original -- which means the slant height and radius are both doubled, then we have two similar solids with scale factor 2; the ratio of surface areas is 4:1. So in this case the surface area is multiplied by a factor of 4, not 2.

\n" ); document.write( "ANSWER: Yes, the surface area is doubled -- IF only the slant height is doubled AND by \"surface area\" you are only talking about LATERAL surface area.

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