document.write( "Question 1172844: A wrought-iron washer is 3.5\" in diameter, 5/32\" thick, and has a hole 1.5\" in diameter. Determine number of washers in a 200 lb. container.\r
\n" ); document.write( "\n" ); document.write( "Check my calculations, please.\r
\n" ); document.write( "\n" ); document.write( "Volume = pi * r^2 * height\r
\n" ); document.write( "\n" ); document.write( "3.1416 * 1.75 * 1.75 * .15625 = 1.5033 cu. in. (gross washer volume).\r
\n" ); document.write( "\n" ); document.write( "1.5033 - 1.5 = .0033 cu. in.\r
\n" ); document.write( "\n" ); document.write( "200 / .0033 = 60606 \n" ); document.write( "

Algebra.Com's Answer #797979 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi  
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document.write( "Attempting to keep calculations to a minimum:
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document.write( "Subtracting one Volume from another:
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document.write( "V = πr^2d
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document.write( "Washer volume:
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document.write( "(5/32)π[ (7/4)^2 - (3/4)^2]   |NOte: (7/4)^2 = (7/4)(7/4) = 49/16
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document.write( "(5/32)π( 49/16 - 9/16)
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document.write( "(5/32)π( 40/16)
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document.write( "(5/32(10/4)π = 1.2272in^3   
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document.write( "Weight= .28 lb/in^3  (per Chart of Weights Student used)
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document.write( "1.2272in^3 (.28lb/in^3) = .3436lb
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document.write( "200lb/.3436lb = 582.07 = 582 is the number of washers in a 200 lb. container.
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document.write( "Demonstrates: 
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document.write( "At times, a problem may not supply all the information one needs...  \n" );
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