document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172843>Question 1172843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has perimeter 128 cm and its length is 1 cm more than twice its width.<BR>\n" );
document.write( "Find the dimensions of a rectangle given that its perimeter is 128 cm and its length is 1 cm more than twice its width.<BR>\n" );
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document.write( "Set up your solution using the variables L for the length, W for the width, and P for the perimeter. \r<BR>\n" );
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document.write( "Part a: Using the definition of perimeter, write an equation for P in terms of L and W.<BR>\n" );
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document.write( "Part b: Using the relationship given in the problem statement, write an equation for L in terms of W.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797971 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2w; worth drawing this.<BR>\n" );
document.write( "(1/2)P=L+W (not commonly used but simpler in some ways.)<BR>\n" );
document.write( "64=L+W, but L=2W+1<BR>\n" );
document.write( "so 64=2W+1+W<BR>\n" );
document.write( "3W=63<BR>\n" );
document.write( "W=21 cm<BR>\n" );
document.write( "L=43cm<BR>\n" );
document.write( "perimeter is 2(21)+2(43) or 128 cm.\r<BR>\n" );
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