document.write( "Question 1172834: how to solve 3x + y - 2 = 0 and 2x - y - 3 = 0
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Algebra.Com's Answer #797949 by mahikab(11)![]() ![]() ![]() You can put this solution on YOUR website! We can use systems of equations! \n" ); document.write( "We can keep the variables on the right side of the equation, while keeping the constants on the right: \n" ); document.write( "So 3x + y - 2 = 0 becomes 3x + y = 2 \n" ); document.write( "So 2x - y - 3 = 0 becomes 2x - y = 3 \n" ); document.write( "Now we can use systems of equations: \n" ); document.write( " 3x + y = 2 \n" ); document.write( "+ (2x - y = 3) \n" ); document.write( "----------------- \n" ); document.write( "3x+2x + y-y = 2+3 \n" ); document.write( "5x + 0 = 5 \n" ); document.write( "x = 1 \n" ); document.write( "Since we know what one of the variables equal, we can plug in the value of x in one (or both) of our equations. \n" ); document.write( "3(1)+y = 2 \n" ); document.write( "y = 2-3 \n" ); document.write( "y = -1 \n" ); document.write( "Let's check if it works for our other equation as well! \n" ); document.write( "2(1)-y = 3 \n" ); document.write( "2-y=3 \n" ); document.write( "-y = 3-2 \n" ); document.write( "-y = 1 \n" ); document.write( "y = -1 \n" ); document.write( "So, the answer to our problem is: \n" ); document.write( "x = 1 \n" ); document.write( "y = -1 \n" ); document.write( "Also could be written as (x,y) -> (1, -1) \n" ); document.write( " |