document.write( "Question 1172795: For 3 ensurance companies, the chances that a client closes an ensurance deal are 15%, 16% , 17%. Three clients enter simultaniously, one in each of the 3 companies. What's the probability of?
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Algebra.Com's Answer #797911 by ikleyn(52879) $\"\"$ $\"About$

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\n" ); document.write( "For 3 $\"highlight%28cross%28ensurance%29%29\"$ insurance companies, the chances that a client closes an $\"highlight%28cross%28ensurance%29%29\"$ insurance deal are 15%, 16% , 17%. T
\n" ); document.write( "Three clients enter $\"highlight%28cross%28simultaniously%29%29\"$ simultaneously, one in each of the 3 companies. What's the probability of?
\n" ); document.write( "1. 2 clients close an $\"highlight%28cross%28ensurance%29%29\"$ insurance deal?
\n" ); document.write( "2. At least 2 clients close an $\"highlight%28cross%28ensurance%29%29\"$ insurance deal?
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document.write( "(1)  P = P(1st yes, 2nd yes, 3rd no) + P(1st yes, 2nd no, 3rd yes) + P(1st no, 2nd yes, 3rd yes) = \r\n" );
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document.write( "       =   0.15   * 0.16*   (1-0.17) +   0.15 * (1-0.16) * 0.17    + (1-0.15) * 0.16   * 0.17    = 0.06446.   \r\n" );
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document.write( "(2)  P = P(1st yes, 2nd yes, 3rd no) + P(1st yes, 2nd no, 3rd yes) + P(1st no, 2nd yes, 3rd yes) +  P(all 3 yes)  = \r\n" );
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document.write( "       =   0.15   * 0.16*   (1-0.17) +   0.15 * (1-0.16) * 0.17    + (1-0.15) * 0.16   * 0.17    + 0.15*0.16*0.17 = 0.06854.   \r\n" );
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