document.write( "Question 1172767: Equilateral triangle ABC has altitude AD of length 12 mm. Median AE of triangle ABD is drawn. What is the area of triangle AEC in mm²? \n" ); document.write( "
Algebra.Com's Answer #797887 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Triangles ABD and ACD are 30-60-90 right triangles, with long leg AD having length 12. The side length of triangle ABC is then \"12%2A%282%2Fsqrt%283%29%29+=+24%2Fsqrt%283%29+=+8%2Asqrt%283%29\".

\n" ); document.write( "AD is half that side length, or \"4%2Asqrt%283%29\"; ED is half again as much, or \"2%2Asqrt%283%29\".

\n" ); document.write( "So the base of triangle AEC has length \"6%2Asqrt%283%29\".

\n" ); document.write( "Then the area is one-half base time height:

\n" ); document.write( "\"%281%2F2%29%286%2Asqrt%283%29%29%2812%29+=+36%2Asqrt%283%29\"

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