document.write( "Question 109423: 4 people, starting on the same side, want to cross a bridge. All have to be across in 17 minutes or less. It is night. They have one flashlight, which must accompany them across. A max of 2 people can go at once. The flashlight cannot be thrown. It must be walked back and forth. Each person walks a different speed and pairs must walk together at a rate of the slower person's pace. The 4 persons crossing times are as follows: P1 = 1 min.; P2 = 2 min.; P3 = 5 min., P4 = 10 min. How do you solve this? \n" ); document.write( "
Algebra.Com's Answer #79788 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! this cannot be done in the allotted time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the fastest person (P1) must accompany each crossing so that the flashlight returns in the shortest time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10+5+2=17 ... but that does not take into account the returning of the flashlight\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "**ENLIGHTENMENT** ... thanks to Dushenko\r \n" ); document.write( "\n" ); document.write( "the two slowest must cross together to minimize their time impact \n" ); document.write( "... this means the two fastest must cross together leaving a \"faster\" person on each side to return the light\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the two fastest people cross first, one stays and the other returns with the light \n" ); document.write( "... next, the two slowest people cross and the faster returns with the light \n" ); document.write( "... lastly, the two fastest people cross \n" ); document.write( " |