document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172743>Question 1172743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Law of Sines to solve the triangle. Round your answers to two decimal places.\r<BR>\n" );
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document.write( "B = 2° 45',  b = 6.7,  c = 5.7\r<BR>\n" );
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document.write( "C=____°<BR>\n" );
document.write( "A=_____°<BR>\n" );
document.write( "a=_____ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797860 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b/sinB=6.7/sin 2.75deg=139.65<BR>\n" );
document.write( "c/sinC=139.65, so c/139.65=sin c=0.0408. Take arc sin both sides and C=2.34 deg or 2 deg 22'<BR>\n" );
document.write( "a/sin A=139.65, angle A is 180-2.75-2.34=174.91 deg,<BR>\n" );
document.write( "sin 174.91=0.0887<BR>\n" );
document.write( "a=12.390 </SPAN>\n" );
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