document.write( "Question 1172701: How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines) \n" ); document.write( "

Algebra.Com's Answer #797815 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines)
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\n" ); document.write( "We can find the height. A right triangle is formed, using sin(41), hypotenuse = 120 and side opposite is h,
\n" ); document.write( "so we have: sin(41) = $\"h%2F120\"$
\n" ); document.write( "h = 78.7271
\n" ); document.write( "A = $\"1%2F2\"$ b*h, where b=200 and h=78.73
\n" ); document.write( "A = $\"1%2F2\"$ *200*78.7271
\n" ); document.write( "A = 7872.7 sq/units \n" ); document.write( "

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