document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1172665>Question 1172665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hunter invested $750 in an account paying an interest rate of 6 5/8% compounded continuously. London invested $750 in an account paying an interest rate of 6 1/2% compounded daily. After 18 years, how much more money would Hunter have in his account then London, to the nearest dollar? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #797788 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=797788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. P=750*e^(rt)=750*e^(.06625*18)<BR>\n" );
document.write( "=750*e^1.1925<BR>\n" );
document.write( "=$2471.48 or $2471<BR>\n" );
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document.write( "b. P=750(1+(0.0650/365))^(365*18)<BR>\n" );
document.write( "=$2416.24 or $2416<BR>\n" );
document.write( "-<BR>\n" );
document.write( "The difference is $55.24 or $55. </SPAN>\n" );
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