document.write( "Question 1172668: The force of attraction (F) between two opposite electric charges varies inversely as the square of the distance (d) between them. If F = 30 newtons when d = 5 meters, find F when d = 12 meters.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #797784 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
The force of attraction (F) between two opposite electric charges varies inversely as the square of the distance (d) between them.
\n" ); document.write( "
\r\n" );
document.write( "Let's pause here.\r\n" );
document.write( "\r\n" );
document.write( "For all proportion problems, start with this:\r\n" );
document.write( "\r\n" );
document.write( "Varying           \"directly\" or product of \"jointlys\" or 1 if none \r\n" );
document.write( "quantity  = k ∙ ----------------------------------------------------------\r\n" );
document.write( "                inversely variable or product of \"inverselys\" or 1 if none\r\n" );
document.write( "\r\n" );
document.write( "In this problem the varying quantity is F. There are no \"directly\" or \"jointly\"\r\n" );
document.write( "variable.  So the numerator is the number 1.  We have one inversely, d2. So we\r\n" );
document.write( "have F on the left, 1 on the top of the fraction and d2 on the bottom:\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2Ck%2Aexpr%281%5E%22%22%2Fd%5E2%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "-----------------------\r\n" );
document.write( "\r\n" );
document.write( "
If F = 30 newtons when d = 5 meters,
\r\n" );
document.write( "Let's pause again here.\r\n" );
document.write( "Let's substitute 30 for F in \"matrix%281%2C3%2CF%2C%22%22=%22%22%2Ck%2Aexpr%281%5E%22%22%2Fd%5E2%29%29\", and 5 for d2>/sub>, and solve for k:\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2C30%2C%22%22=%22%22%2Ck%2Aexpr%281%5E%22%22%2F5%5E2%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "Put 1 under 30 and write 52 as 25:\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2C30%2F1%2C%22%22=%22%22%2Ck%2F25%29\"\r\n" );
document.write( "\r\n" );
document.write( "Cross-multiply:\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2Ck%2C%22%22=%22%22%2C750%29\"\r\n" );
document.write( "\r\n" );
document.write( "Now we substitute 750 for k in \r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2Ck%2Aexpr%281%5E%22%22%2Fd%5E2%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2C750%2Aexpr%281%5E%22%22%2Fd%5E2%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2C750%5E%22%22%2Fd%5E2%29\"\r\n" );
document.write( "\r\n" );
document.write( " find F when d = 12 meters.\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2C750%5E%22%22%2F12%5E2%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2C750%2F144%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2CF%2C%22%22=%22%22%2C5.208333333%29\" newtons.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );