document.write( "Question 1172683: VARIATION:\r
\n" ); document.write( "\n" ); document.write( "The distance (d) from the center of the seesaw varies inversely as the weight (w) of a person. JB who weighs 50 kg sits 3 feet from the fulcrum. How far from the fulcrum must JP sit in order to balance with JB if he weighs 35 kg? \n" ); document.write( "

Algebra.Com's Answer #797773 by ikleyn(52803) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "The governing equation for seesaw to be in equilibrium is\r\n" );
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document.write( "    50*3 = 35*x.\r\n" );
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document.write( "Find x from this equation.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Formulation of this simple problem is artificially made so unjustly complicated
\n" ); document.write( "using these mysterious names JB and JP,\r
\n" ); document.write( "\n" ); document.write( "that it is just the time to call for the urgent medical assistance.\r
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